Hello:
Ok a bit of topic, but wanted to generate some CO2 and stumbled upon this that is apparently the correct ratio of household vinegar and baking soda to efficiently generate a given amount of C02.
But I have access to cleaning vinegar which is 10% acetic acid vs 5%.
SO, does this mean I can half the amount of vinegar for the given amount of baking soda. I can just use 100ml of vinegar and 13.9 grams of Baking soda?
The reaction is as follows:
NaHCO3 (aq) + CH3COOH (aq) ......> CO2 (g) + H2O (l) + CH3COONa (aq)
Thus: 84gmw 60gmw 22.4L gas (i mole)
THE APROX CALCULATIONS ARE:
Because Vinegar is only 5% acetic acid - 200ml of vinegar has about 10 grams of acid or 16.6% of a mole of acetic acid.
We need 16.6% of a mole of baking soda which is 13.9 grams.
Thus you would get 16.6 % of a mole of gas or 3.7 Liters of CO2 gas which equals about .97 gallons of gas
Ok a bit of topic, but wanted to generate some CO2 and stumbled upon this that is apparently the correct ratio of household vinegar and baking soda to efficiently generate a given amount of C02.
But I have access to cleaning vinegar which is 10% acetic acid vs 5%.
SO, does this mean I can half the amount of vinegar for the given amount of baking soda. I can just use 100ml of vinegar and 13.9 grams of Baking soda?
The reaction is as follows:
NaHCO3 (aq) + CH3COOH (aq) ......> CO2 (g) + H2O (l) + CH3COONa (aq)
Thus: 84gmw 60gmw 22.4L gas (i mole)
THE APROX CALCULATIONS ARE:
Because Vinegar is only 5% acetic acid - 200ml of vinegar has about 10 grams of acid or 16.6% of a mole of acetic acid.
We need 16.6% of a mole of baking soda which is 13.9 grams.
Thus you would get 16.6 % of a mole of gas or 3.7 Liters of CO2 gas which equals about .97 gallons of gas