how to figure out water volume on a hexagonal fish tank?

if my calculations are correct.. each side being the base of a triangle.. with base 24 and a height of 21(half the diameter).. and the tank having a height of 29.5"

not subtracting the space from the overflow each side would have a volume of 7,434 cubic inches ((21x24)/2)x29.5.. being that there are 6 sides

comes to a total volume of 44,603 cubic inches.. converted to gallons roughly is 193 gallons of water..
 
For a drain, bigger's always better. I think my 90 has a 1 1/4" drain in the overflow. For return, it will depend on how big a pump you want on there. In a way, you can't really oversize it, since you can always put a reducing bushing before and/or after the bulkhead. If it's too big, the worst-case scenario is you'll have some extra PVC fittings to buy.
 
picture may be decieving but the hole in the overflow looks to be pretty small.. the return holes wont matter as much.. as the water overflowing can only be equal to the water returning.. but the water may not be able to drain as quick.. as bromion stated bigger is always better on the drain... that make any sense at all.. lol

may want to put a durso standpipe in there too.. noise could bug after a while..
 
Yes, a standpipe would be advisable. I use a Stockman style standpipe. If you search it on google the plans should come up near the top. It's similar to Durso but more compact (I could not fit the Durso in my overflow, as it requires an elbow). A standpipe is usually made of PVC sized larger than the drain bulkhead. Consider that when you make your drainage hole.
 
Looks to me like a typical one inch drain bulkhead with 3/4 returns. Good for up to 600 gph. My choice would be a bigger drain for "what ifs" but I don't think you can do anything about the hole size now. The bottom is most likely tempered meaning no drilling.
 
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