Depends on how "dirty" your water is. If the water were crystal clear (and nobody's truly is), then it wouldn't attenuate light any more than going through air. BTW, Joshi's PFFD numbers at taken at 18", and you can find what they are at any distance by multiplying by the square of the ratio of distances. So, at "b" inches, the amount of PAR to expect would be (b/18)^2X(Joshi's PAR number). You'll find that the intensity is less than this predicts because of DOC, dyes, etc. in your water.