36.842105ppt. The absolute amount of salt does not change...only it's relative distribution in the remaining water changes. Forget about the units...ppt is really grams of salt per kilogram of saltwater. All that is important for your question is some basic math:
35ppt starting ppt.
100g starting water amount (before evaporation).
95g ending water amount (after evaporation).
The ending water amount is therefore 95% (or 0.95) of what it was prior to evaporation.
35ppt / 0.95 (you are now "distributing" the 35ppt absolute amount of salt over 95% of the original amount of water).
I was debating whether to reconfigure my sump. Realized that, the way it is now set up, if my 100 gallon system lost 5 gallons of water (say because the ATO stopped ATOing while I was out of town), the return pump section would run dry. I based my design on a malevsreef design (http://www.melevsreef.com/acrylics/sumps/f/sump_f.html) but now realize I made the return section too narrow.
I was wondering if the evaporation of 5 gallons would cause a nuclear meltdown no matter how the sump is configured, but it appears that is not the case. So I'll reconfigure it. Thank the flying spaghetti monster I can get the sump out of the stand without a problem.
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