DeadlyMuffin
Member
I'm one of those people who can't leave well enough alone and wants to know how things work, so simply using the online calculators to find the amounts of Calcium/Alk to add isn't enough for me. I'd like to see the math myself.
Alkalinity: My test kit reads in KH (which is a confusing measurement) so I'm going to divide by 2.8 to get meq/L (where does this number come from? I found it here: http://www.advancedaquarist.com/issues/feb2002/chemistry.htm).
So say I have a 100L tank at 6 KH (2.143 meq/L) and I want to go to 8 KH (2.857 meq/L). Difference is .714 meq/L or, with the 100 L tank, 71.4 meq.
The alk part of my two part is using baking soda which (assuming it's pure!) is 42g/mol, so to get 71.4 meq I need .0714 mol or 3g of pure baking soda.
Is this the right way to do the calculation? Seems like the same sort of thing we did in general chemistry (or high school for that matter). Looking at it this way, is it necessary to dissolve the baking soda in water at all if you can measure it by mass? If it's dissolved you would of course have to take into account the new tank capacity, although it's probably pretty negligible for a big tank. Is it because the sodium and the bicarbonate don't separate the same if they were simply tossed into salt water as opposed to dissolved in fresh water?
Calcium is measured in ppm, which is a bit weird. Parts per million of... what exactly? I've tried to look this up, but I can't find if it's per million water molecules or by mass, which would be different in salt water than in pure water. If I know how it's being measured, I should be able to convert it to a molarity and do the same sort of calculation I did with alk.
Am I doing this right or am I off in left field here?
Alkalinity: My test kit reads in KH (which is a confusing measurement) so I'm going to divide by 2.8 to get meq/L (where does this number come from? I found it here: http://www.advancedaquarist.com/issues/feb2002/chemistry.htm).
So say I have a 100L tank at 6 KH (2.143 meq/L) and I want to go to 8 KH (2.857 meq/L). Difference is .714 meq/L or, with the 100 L tank, 71.4 meq.
The alk part of my two part is using baking soda which (assuming it's pure!) is 42g/mol, so to get 71.4 meq I need .0714 mol or 3g of pure baking soda.
Is this the right way to do the calculation? Seems like the same sort of thing we did in general chemistry (or high school for that matter). Looking at it this way, is it necessary to dissolve the baking soda in water at all if you can measure it by mass? If it's dissolved you would of course have to take into account the new tank capacity, although it's probably pretty negligible for a big tank. Is it because the sodium and the bicarbonate don't separate the same if they were simply tossed into salt water as opposed to dissolved in fresh water?
Calcium is measured in ppm, which is a bit weird. Parts per million of... what exactly? I've tried to look this up, but I can't find if it's per million water molecules or by mass, which would be different in salt water than in pure water. If I know how it's being measured, I should be able to convert it to a molarity and do the same sort of calculation I did with alk.
Am I doing this right or am I off in left field here?