Perhaps I am incorrect in my assumption? I think I am over my head. :lol:
This article may help:
Processing Environments: Effective Use of Chlorine
http://www.ag.auburn.edu/poul/virtuallibrary/mckeeprocessingenvironschlorine.html
From this article:
Example Usage Calculations
I. Calculation for 200 ppm (0.02% Chlorine) Solution from Standard Bleach
1. Start with Standard Bleach is 5.25% (0.0525) Sodium Hypochlorite (NaCIO)
2. Sodium Hypochlorite is 47.62% (0.4762) Chlorine
3. To calculate the amount of Chlorine in Standard Bleach
0.0525 (sodium hypochlorite) times 0.4762 (percentage of chlorine in sodium hypochlorite equals 0.025 or 2.5%
4. Calculate Y, The ratio of final solution volume-to-standard bleach volume required to achieve a solution of 200 ppm chlorine concentration:
Y = (the amount of chlorine in bleach) / (desired solution chlorine concentration)
Y = 2.50% / 0.02% = 125 to 1.0
A 125 unit volume of 200 ppm final solution will consist of 124 units water and 1.0 units of standard bleach, a 124 to 1.0 ratio of water-to-standard bleach.
5. Calculate X, the ratio of standard bleach volume-to-final solution volume required to achieve a solution of 200 ppm chlorine concentration:
X = (desired solution chlorine concentration) / (the amount of chlorine in bleach)
X = 0.02% / 2.50% = 0.008 (0.80%) to 1.0
A 125 unit volume of 200 ppm final solution will consist of 0.8% bleach (1.0 units) and 99.2% water (124 units), a .0081 to 1 ratio of standard bleach-to-water.
II. Calculation for 200 ppm (0.02% Chlorine) Solution from Sodium Hypochlorite (47.62% chlorine)
1. Calculate Y, The ratio of final solution volume-to-sodium hypochlorite volume required to achieve a solution of 200 ppm chlorine concentration
Y = (the amount of chlorine in sodium hypochlorite) / (desired final solution chlorine concentration)
Y = 47.62% / 0.02% = 2,381 to 1.0
A 2,381 unit volume of 200 ppm final solution will consist of 2,380 units water and 1.0 units of sodium hypochlorite, a 2,380 to 1.0 ratio of water-to-sodium hypochlorite
2. Calculate X, the ratio of sodium hypochlorite volume-to-final solution volume required to achieve a solution of 200 ppm chlorine concentration
X = (desired solution chlorine concentration) / (amount of chlorine in sodium hypochlorite)
X = 0.02% / 47.62% = 0.0004 (0.040%) to 1.0
A 2,381 unit volume of 200 ppm final solution will consist of 0.040% sodium hypochlorite (1.0 units) and 99.6% water (2,371.376 units), a .000402 to 1 ratio of sodium hypochlorite-to-water.