I decided I better explain how LED's work because I need to explain how I decide which MeanWell power supplies I will be using with each of the LED types (UV, Royal Blue, Blue, Cool White, Warm White, Red and Green)
One important factor about LED's is that LED's are current driven devices, not voltage driven.
Most people are familiar with the typical volts i.e. 120Vac used in homes. If we look at a typical incandescent light bulb used in a home, these devices are voltage controlled.
In this type of circuit the voltage stays constant and the current changes. So what we need to understand is the relationship of watts to volts to amps, and how these relationships work for an incandescent bulb and an LED. The formula to calculate current is: watts / volts = current.
In a home circuit the voltage stays the same, but the current varies according to the type of device you are using. If you ever popped a circuit breaker (not GFCI) the reason you did is because you exceeded the current in the circuit not the voltage.
A typical 120 Watt incandescent bulb in a typical 120Vac fixture uses 1 Amp of current. Using the formula we calculate the math as follows: 120 watts / 120 volts = 1 amp. Now if we put 2 light bulbs on the same circuit in parallel then the voltage stays the same across both bulbs (120Vac), but the current goes up to 2 amps. Again using the formula we calculate the math as follows: 240 watts / 120 volts = 2 amps. So each bulb uses 120Vac @ 1 amp.
Add three 120 Watt bulbs in parallel the current goes to 3 amps and so on. So for a normal home light circuit, the voltage remains the same and the current changes. When you dim an incandescent bulb you lower the voltage across the bulb which causes the current to drop. This is important when I talk about how to dim an LED circuit. This is also why LED bulbs used in the home require a special dimming switch.
Reminder, LED's are current driven devices, not voltage driven. So now for an LED to keep the current constant in the circuit the voltage has to increase.
For this example we are going to assume that the LED power supply is providing 1 amp of current, and the LED is a 3 Watt LED so the voltage drop across the LED is 3Vdc. Since we know the current is 1 amp and the LED is 3 Watts the equation now becomes volts = watts/current 3 volts = 3 watts/1 amp.
Not so different than the incandescent bulb example, right. Well, not really.
Remember I mentioned that LED's are current driven devices. Now here is what happens when we put two LED's in a series circuit.
We calculated above that the voltage needed for each 3 Watt LED is 3Vdc @ 1 amp. So with 2 LED's in series we add the volts together and keep the current at 1 amp.
We now have 6Vdc (3Vdc x 2) across the the two LED's. So when we do the math we get 6Vdc x 1 amp = 6 watts.
If we put three 3 Watt LED's together in series we get 9Vdc for the three LED's still at the 1 amp which uses 9 watts.
So for a series LED circuit using 1 amp of current and 3 Watt LED's the voltage increases by 3Vdc as you add more LED's.
This is important because the power supply components needed to make your LED circuit work are specific to LED technology.
To drive an LED circuit you need a power device that varies its output voltage and keeps its current output constant.
The MeanWell power supplies I use are rated for a specific current output and a specific maximum Vdc. The specs on the LED power supply will determine how many LED's you can put in series on one LED power supply. I'll explain more about this later on.
So now that you understand that LED's are constant current devices, how the heck do we dim LED's. Well you vary the current going through them. Wait a minute we just talked about LED's as being constant current devices. Yes the are, but you can change the current level which will either increase or decrease the brightness of the LED. In home circuits we would change the voltage to dim a light, with LED's we change the current level. The MeanWell LED power supplies I use have a set of inputs which I mentioned in a previous post that can use either a resistive element, a PWM signal or an Analog (0-10Vdc) signal to increase or decrease the current output.
Real World Example
If I look at the specs for the CREE Cool White LED's I am using the data indicates the following:
Max Current 1500mA (1.5amps) Recommended current 350-1100mA Forward Voltage 2.85-3.4Vdc (as you change the current the voltage drop across the LED changes) Earlier I was using 3Vdc in my example. In the real world, the number will be dictated by the LED type. I typically use 3.3Vdc in my math equations unless an LED has a higher Vdc spec)
MeanWell LPF-60D-54 (the "œD" indication in the product number indicates that this power supply has the ability to be dimmed)
OUTPUT Specs
DC VOLTAGE: 54V (this is the maximum voltage that the power supply can provide. This is important because this will determine how many LED's I can have. Remember that 3.3Vdc I mentioned above.)
CONSTANT CURRENT REGION: 32.4 ~ 54V (what this spec indicates is that if the number of LED's you are using results in a total net Vdc of less than 32.4Vdc then the power supply will not provide you with the constant rated current of 1.12A) Since I always make sure I am above the minimum, I don't have to worry about this.
RATED CURRENT: 1.12A (1120ma) (maximum constant current that the power supply can provide. This is important, because you need to make sure the LED's you are using can handle this value. My CREE CW as per the specs above would be fine with this current value.)
RATED POWER: 60.48W (using our watts = volts x amps 60.48 Watts = 54Vdc x 1.12 amps)
Ok so how many of the CREE CW LED's can I put on this power supply? The math is easy on this one. It's the DC voltage of 54V/3.3V this number is 16.36 LED's. Since we can't have a partial LED, you would round down. I always round down when calculating the maximum number of LED's. So the maximum would be 16 of the CREE CW LED's. To stay above the power supplies minimum output voltage of 32.4Vdc (to keep the constant current) you would need a minimum of 10 LED's. 32.4V/3.3V which equals 9.81. When calculating the minimum number of LED's I always round up.
Ok that was a lot to take in and I'm hoping I didn't lose anyone with my explanation and/or the math.
If anyone has any questions, please ask there are no dumb questions.