Originally posted by Jamesurq
Are those internal pipe diameters? Probably not. the schedule of the PVC will determine actual internal diameter.
Right, which is why I said 1" ID PVC (ID == inside diameter)
Originally posted by fsn77
Actually, "r" is the radius, not the diameter, making r^2 for 1" pipe = 0.5 * 0.5 = 0.25.
Doh! My bad. You are correct sir.
So 1 foot of 1" ID PVC is 0.0407999044 gallons. So even with 10 feet of pipe, you only have ~0.4 gallons of water. It's such an insignificant amount to worry about. Even with 2" ID PVC you'd only have 0.163199617 gallons per foot.
Originally posted by Travis L. Stevens
Cool information and all, but the original question asks how to determine the total volume of water. You can do this by (length x width x heigth)/231 = ~gallons.
That is incorrect. He asked about the volume of "tubing" (I assume he means pipe). Tubing is cylindrical, not rectangular, therefor you have to use the calculation of volume for cylinders, not rectangles.
And yes, those that mentioned that it's impossible to calculate the volume that LR takes up, I agree. It's much much more than the amount of water that will be in your plumbing.
Bottom line is, you should assume your total system volume is:
volume of tank + volume of sump
Forget all the other fanciness.