gilles0181
New member
Hi,
In search for my 'thunderstorm' idea; i have found this product:
http://www.ghl-store.com/alu-leuchtbalken/led-steuerungen/ledcontrol4active-2.html
Which is a dimmable LED-controller with driver, 4 seperate channels, 5-48V, max 5A dimming through PWM through GND without power supply.
If i read their pictures correct; i have a max. of 48v at my disposal; and all channels in sum should not exceed 5A.
Since 'thunderstorm flashes' are only produced on 2 channels; i am only going to connect these 2 and i wanted the brightest LED light available.
I came up with this; Cree XT-E Premium Cool White LED;
Max Current 1500mA
Recommended current 350-1100mA
Forward Voltage 2.85-3.4
Given the 2 channels; i can devide the 24V and 5A; which would mean i could have 24v + 2.5 on each channel (the other ones are not used)
So i entered the values in the calculator found here (http://ledcalc.com/#calc) tab "Series".
And i came up with this:
Supply Voltage: 24v
Voltage Drop Across LED: 3.4v
Desired LED Current: 1300mA (*)
How many leds connected: 6
(*) Entering 1300mA yields the result of 1090.9mA in the calculator; which is closest to 1100mA which i could find.
The result would be that i could connect 6 LEDs in series; with a 3.3 Ohm resistor.
Am i correct that i then could use 12 LEDs (separated over 2 channels) with 2x 3.3 Ohm resistor to use the driver at optimal level? Or am i missing something?
In search for my 'thunderstorm' idea; i have found this product:
http://www.ghl-store.com/alu-leuchtbalken/led-steuerungen/ledcontrol4active-2.html
Which is a dimmable LED-controller with driver, 4 seperate channels, 5-48V, max 5A dimming through PWM through GND without power supply.
If i read their pictures correct; i have a max. of 48v at my disposal; and all channels in sum should not exceed 5A.
Since 'thunderstorm flashes' are only produced on 2 channels; i am only going to connect these 2 and i wanted the brightest LED light available.
I came up with this; Cree XT-E Premium Cool White LED;
Max Current 1500mA
Recommended current 350-1100mA
Forward Voltage 2.85-3.4
Given the 2 channels; i can devide the 24V and 5A; which would mean i could have 24v + 2.5 on each channel (the other ones are not used)
So i entered the values in the calculator found here (http://ledcalc.com/#calc) tab "Series".
And i came up with this:
Supply Voltage: 24v
Voltage Drop Across LED: 3.4v
Desired LED Current: 1300mA (*)
How many leds connected: 6
(*) Entering 1300mA yields the result of 1090.9mA in the calculator; which is closest to 1100mA which i could find.
The result would be that i could connect 6 LEDs in series; with a 3.3 Ohm resistor.
Am i correct that i then could use 12 LEDs (separated over 2 channels) with 2x 3.3 Ohm resistor to use the driver at optimal level? Or am i missing something?