In my case V(f) was substantially different.. (different colors w/ much diff V(f) but equal chip count)
IF my thinking is correct.. a higher mA driver would solve that problem since those chip differentials would not be as extreme as in my case.. and the voltage "boost" @ higher mA would overcome it ..
As to my understanding trying to run a red and a blue in parallel wouldn't work since the voltage @ mA "latch" wouldn't permit a v(f) high enough to light a blue (say the driver is 250mA constant current) @ 25C ..
and of course the lower the mA the duller..I assume you could extrapolate to close to zero???
sorry, just babbling..
.....babble, babble........that's kind of what I figured, though with a current mirror (just a pair of transistors) you could! Why, I don't know, but you could......
Usually parallel arrays are using the same chips(or combination of chips) in each parallel string, as should be the case using two of the OP's multichips. Though it is possible that they do not both use the same RB diodes (possibly from two different production runs). Otherwise they should be very close in Vf.
Though essentially two of the 50 watt multichips in parallel is really 10 strings of 10 LEDs all wired in parallel so the odds of imbalance get high pretty fast...........