Quiz
- Thread starter cato
- Start date
reeformadness
New member
786,489,238.876 (the 6 has a bar over it)
littlemannin
Premium Member
are those inside or outside dimensions? How thick is the glass? What is the density of the rock and how much/ So many questions!
reeformadness
New member
So this is a serious question? Well if you mean gallons per inch high I guess it is close to 55/20=2.75 gallons per inch. I thought it was one of those trick questions.
reeformadness
New member
btw, littlemanin is right, the figure could be a little less with inside dimensions.
littlemannin
Premium Member
1 gallon is 231 cubic inches. And 1 cubic inch is 0.004329004 gallons
jdieck
New member
If the internal lenght is 48" and the width is 20" it will be 4.1 gallons per inch of height. Assuming those are external and 1/4" glass thickness then it will be 4 gallons
If the internal lenght is 48" and the width is 12" it will be 2.4 galons per inch of height. Assuming those are external and 1/4" glass thickness then it will be 2.3 gallons
By the way assuming no rock the actual aquarium capacity (48Lx12Wx20H) assuming the surface to be 1 inch below the rim and 1/4" thickness then it will be 44.3 gallons which will weight 379.3 pounds and to the rim will be 46.7 gallons and the water will weight about 399.8 pounds.
To 1 inch below the rim with 60 pounds of LR weighted wet and 60 pounds of sand weighted dry the actual water volume will be 37.6 gallons and the content weight (Water sand and rock) will be aprox 442.6 pounds
This might help for additional shapes, volume and weight calculations:
http://home.comcast.net/~jdieck1/volcalc.html
If the internal lenght is 48" and the width is 12" it will be 2.4 galons per inch of height. Assuming those are external and 1/4" glass thickness then it will be 2.3 gallons
By the way assuming no rock the actual aquarium capacity (48Lx12Wx20H) assuming the surface to be 1 inch below the rim and 1/4" thickness then it will be 44.3 gallons which will weight 379.3 pounds and to the rim will be 46.7 gallons and the water will weight about 399.8 pounds.
To 1 inch below the rim with 60 pounds of LR weighted wet and 60 pounds of sand weighted dry the actual water volume will be 37.6 gallons and the content weight (Water sand and rock) will be aprox 442.6 pounds
This might help for additional shapes, volume and weight calculations:
http://home.comcast.net/~jdieck1/volcalc.html
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