oreo57
Well-known member
Right now im having a similar problem... i know the ELN/PLN drivers, but nothing about PSU and LDD. Here's what i got going on...
Looking at making just 2-3 "spot lights" for now to target 3 specific corals. Eventually in the future i plan to upgrade this as i can by adding more "spot lights" until the entire tank is lit with LED as i get more money. So, from what ive seen, LDD and PSU is the way to go... for the spot light im looking at right now. To make each one i plan on
2 cree CW XP-G2 (1500mah)
2 cree RB XT-E (1500mah)
1 semiLED UV (750 mah)
Each color on a separate driver and dismantle with POT
So, for 2 spot lights.
4 CW
4 RB
2 UV
1 LDD 700
2 LDD 1000
Power supply im looking at http://www.invertersupply.com/media/data/DV480.pdf
So, how do i wire this ans work it so that i dont burn the leds out until i get more of them to run full strings? And then... how do i run said strings?
Say you start w/ the 48V power supply..After accounting for LDD "losses" you are left 45V.
Voltage adds in series, so at say 3.6 V(f) - 12 diodes in series.
Basically 3 "pucks" worth for one CW channel.
Same for WW.
Once the first is built, your done.. The LDD will control the voltage so to speak.. First only allowing 14.4V (concentrate on just one channel for now, the others will be similar)
to reach the 4 diodes. When you build the next you just cut the neg and run it to the pos of the next set of 4. now the LDD will "allow" 28.8V.
adding the 3rd puck and you get 43.2V
You now ran out of voltage..
Anyways each channel is figured the same and behaves the same..
After this you need to add more Ldd's and start another "chain"..
Doesn't really matter how many "amps" the power supply has as long as it is initially over 2.7A..(est. BASED solely on adding Ldd's ACTUAL amps would need to be calculated per string)
adding another chain of 3 in parallel.. 5.4A ..
ALL of this is ballpark, but fairly safe..
Remember volts add in series.. Amps in parallel..
you can have as many LED in series on ONE LDD as long as 1)you pick the correct mA for the diode and 2)you don't run out of cumulative v(f)'s (> power supply voltage-3)..
Opp's misread your thread you have only 2,2,1 per "puck"..i'm not rewriting this.. I see no problem, and doesn't really change anything except halving the math BUT I'm not sure about running one diode on an LDD..esp. if it is low in V(f)
If you start w/ 2 it is the same as my one example..INSTEAD of a max of 3 you will max, at least one channel, out after 6 "spots"....
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