rinconmike
Member
I have a 150 Gallon FOWLR and want to calculate the real water volume. I am coming out with a net volume of around 130.8 gallons one way and 138.6 gallons another way. Should I assume 135 is a good estimate and does that sound right?
I am doing this to determine the correct amount of prazipro to dose.
This is how I did it:
Tank is a Perfect 150 with the interior dimensions (holding water) of 71.25" x 17.25" x 25" / 231 which comes out to 134.9 gallons.
I have around 60 pounds of pukani rock. I tried measuring them to get a general idea and come out with an equivalent displacement of 5.5 gallons (1284 cubic inches / 231).
I then have sand. I do not remember the weight of sand I have and it is shot all over the tank (trigger). Some areas I see the glass, other areas 2" to 3". Using a number of 1.5" depth x 17.25" 71.25" /231 = 8 gallons.
So the Tank Net is 134.9 - 5.5 - 8 = 121.4 gallons
Then for the the sump I have:
29.5 x 14.5 x 7/ 231 = 12.96 gallons
Less rock rubble volume of
19 x 14.5 x 5 / 231 = 5.96 but lots of voids so assume still 40 water so
5.96 - 5.96 x .4 = 3.6 gallons
So sump holds 12.96 - 3.6 = 9.4 gallons
Total Volume is 121.4 + 9.4 = 130.8
I am assuming the 1" returns and drains is negligible.
A second method is this site:
http://reef.diesyst.com/volcalc/volcalc.html
I am pretty sure I have around 60 pounds of live rock and a 20 pound coral skeleton in the display and 20 pounds of LR in the sump. But do not recall how much sand. I am guessing 60 pounds.
This yields 138.6 gallons.
thanks,
Mike
I am doing this to determine the correct amount of prazipro to dose.
This is how I did it:
Tank is a Perfect 150 with the interior dimensions (holding water) of 71.25" x 17.25" x 25" / 231 which comes out to 134.9 gallons.
I have around 60 pounds of pukani rock. I tried measuring them to get a general idea and come out with an equivalent displacement of 5.5 gallons (1284 cubic inches / 231).
I then have sand. I do not remember the weight of sand I have and it is shot all over the tank (trigger). Some areas I see the glass, other areas 2" to 3". Using a number of 1.5" depth x 17.25" 71.25" /231 = 8 gallons.
So the Tank Net is 134.9 - 5.5 - 8 = 121.4 gallons
Then for the the sump I have:
29.5 x 14.5 x 7/ 231 = 12.96 gallons
Less rock rubble volume of
19 x 14.5 x 5 / 231 = 5.96 but lots of voids so assume still 40 water so
5.96 - 5.96 x .4 = 3.6 gallons
So sump holds 12.96 - 3.6 = 9.4 gallons
Total Volume is 121.4 + 9.4 = 130.8
I am assuming the 1" returns and drains is negligible.
A second method is this site:
http://reef.diesyst.com/volcalc/volcalc.html
I am pretty sure I have around 60 pounds of live rock and a 20 pound coral skeleton in the display and 20 pounds of LR in the sump. But do not recall how much sand. I am guessing 60 pounds.
This yields 138.6 gallons.
thanks,
Mike
