jeffbrig
Premium Member
<a href=showthread.php?s=&postid=9716018#post9716018 target=_blank>Originally posted</a> by REDDAWG43
As per Armando Bengochea (his RC is not working)
Ok, here’s what I have calculated. Using a low consumption powerhead like the koralias (3.5 watts) means that it is .0304 amps. (amps x 115 volts = 3.5 watts) So using a power inverter at 90% efficiency, then that makes the powerhead consume .0338 amp (.0304 / .90 = .0338 amps) Now if you get a deep cycle battery like the 12 volt military batteries made by US Battery which has an Amp Hour rating of 110, then that means that 110 / .0338 amps will give you 3254 hours of usage which should give you 135 days of usage. Now I know that one will never need that many days of continuous use but if you add a second powerhead it would still have plenty juice to power them. Then you can charge the battery once you get your power back J
I'm not sure the assumptions work here. You're applying the current draw of a 3.5watt AC pump to a battery rated at 12V DC. In reality, the battery has to provide significantly more current to generate the 120V AC sinewave that drives the pump. The conversion factor is probably ~10x. Also, I'd be surprised if power inverters are really 90% efficient.
If you really want to maximize battery life, a little bit of PVC and a small airpump can make an airlift that's VERY effective at creating water movement. From a movement/watt standpoint, that's probably the best option out there.