Anemonebuff
New member
You could have higher amps, but if the volts are low, you could use less wattage. Our electric bills are billed in watts.
You could have higher amps, but if the volts are low, you could use less wattage. Our electric bills are billed in watts.
You are consuming the output volts x amps to equal wattage. Not the input volts x amps.
However I note some companies are moving to charging for real VA rather than watts,
Im sure if they did, it would be to save us money, right?![]()
Because you reduce the amount of volts to power the unit. You run 12 LEDs at about 9-10VDC not the full 110VAC coming from the wall. There is some drop off from AC to DC, but that full 110VAC is not being applied.
http://reefledlights.com/how-to-adjust-your-eln-60-48-driver/
Here is my 2 cents.
The power company will charge you base on the power usage means equal to 110VAC x Amp to turn on the driver and loads (led in this case) x power factor (PF=1) so you will pay the wattage of 110VAC x Amp. Leds will acting like the load, when the load increase the 110VAC Amp will increase and the wattage will increase.
The actual usage power will not accurate if only calculate base on output voltage and output current because some of power loss due to operated all the components inside the driver and output power factor. Low power factor will have less power efficient = more power loss to operate the led.
Actually, you have to measure the amps in the same circuit as the volts. The amps change from input to output, just like the volts change.
What you are consuming is really the input voltsxamps, because that includes any inefficiencies. What you are charged for by the power company, is most often only the actual or resistive part of that - meaning you have to also multiply by power factor, which finally gives you watts rather than just VA.
However I note some companies are moving to charging for real VA rather than watts,
Example a 250 watt MH doesn't draw 250 watts, with a PF at .9 it will draw 250/.9 = 277.78 watts or a 80 watt LED with a driver that has a .64 PF - 80 watts/.64 = 125 watts
Then why are people running the LED driver showing almost 1/4 that wattage draw when measuring with a killawatt meter?
What LED Driver? I only gave the one I saw posted very early in this post. If you give me the specifications of a particular driver I can give you the results. With most LED systems you are not going to have a driver that has a PF that poor and most of them are dimmed down, example I have a friend who has the aquailluminations running at only 70% so there is more savings. I think everybody is missing the big point if you have an 80 watt LED light that draws 120 watts but you are replacing 250 watt MH that draws 270 watts then you are saving over 50% on your energy and air conditioning bill.