@ TropTrea: Your calculation assumes that they have exactly the same VF in all four chip's. This is normally not the case. It may differ slightly. If the relationship between voltage, current and resistance is linear, it does not matter but a LED is a diode and then this relationship is not linear. A small change in voltage leads to a large change in resistance and hence a large change of current. Therefore, we know nothing about the magnitude of the current until we measured it to each chip. The resistance is also affected by the working temperature.
Look at this diagram for a single Cree LED (page 4, Electrical Characteristics). For example, a change of V from 3 to 3.25 V will leads to a change in current from 500 mA to 1500 mA. And vice versa. If you use 500 mA as constan current - you will have 3 V as VF and if you use 1500 mA -> FV=3.25 V
When using a constant current source and parallel connections, it is quite true that one can divide the total current, in this case, in 4 parts, but they are only equal if each chip's FV is the same. Multichip is a bit special for inside such chip there are both parallel and series connections. Reputable manufacturers use individual LEDs from the same bin in the same chip. But when you get your chip you do not know if all the chips come from the same origin bin of LED and therefore the VF can vary between different chip. If you run a single chip or chip´s i serie - it does not matter because the driver will hold the current constant (constan current driver) but if you shall distribute the drive´s constant current between two or more parallel strings - then play the single chip´s VF an important role in how the current is distributed among the chips
Most likely, it works but you can never be sure. It is best to measure individual currents of each chip and using Fuse protection. In any case, I would proceed in that way if I use a parallell conection.
@ Xssx If you do not use fuses, you can do so that you connect all plus with each other and all negative with each other by going from part to part. If using a fuse , connect one end of fuse 1 to positive on chip 1, then connect the other end of fuse 1 to positive on the driver. Do the same withh fuse 2 - 4 and chip 2 - 4.
I hope you understand what I mean.
@ Maglofster: It works well I can see
Sincerely Lasse