RichConley
New member
I think a behind-the-tank sump would be a great idea, for an INWALL, with a fishroom. The basement is such a waste of electricity.
<a href=showthread.php?s=&postid=10366343#post10366343 target=_blank>Originally posted</a> by RichConley
I think a behind-the-tank sump would be a great idea, for an INWALL, with a fishroom. The basement is such a waste of electricity.
If thats the case it's still wrong. If you have a pump in another room on same level and it has to go 25 ft (example) to get to the tank. Placing the same pump in the basement uses no more electricity. It's still the same pump, still the same load. It's not going to use more amps just because it has to got vertical over horizontal. The amps put out by the pump are the same regardless of which floor it's on.<a href=showthread.php?s=&postid=10377744#post10377744 target=_blank>Originally posted</a> by tperk9784
Pretty sure he means it takes more electricity to pump water up to the next floor than it takes to pump it from the next room on the same level.
I know that but if the pump is doing 1000gph @25 ft it's going to use the same amp's to run it regardless of if the head is pointed north, south, east, or west. It might work a little harder going vertical and that's only because of back pressure and gravity but if that is what it's was rated to do, it will do it. Now the same pump set under you tank w/ say 10 feet of head would produce a greater head but still the same amount of electricity. It can't decide on it's own to pull more electricity then it was designed to. The only thing that can be exceeded is the current flowing thru the gauge of wire it uses to supply the pump power or the circuit supporting it. That's my point. It's really to bad that pumps don't work like say car amps. They only use the power needed to move the speaker at the volume you set them. 1000 watt amp will not put out 1000 watts if the volume only requires 200 watts. Pumps run wide open.... (if you know of a pump with a variable electric current, please point me to it.)<a href=showthread.php?s=&postid=10378297#post10378297 target=_blank>Originally posted</a> by seattlerob
nasek718: it takes a bigger pump to create the same flow when comparing 0 ft to 25 ft. It's called head pressure I believe.
In other words, a return pump that is 1000gph at 0 ft head will be much less gph at 25 ft head. In fact, most pumps will have a maximum head pressure rating.
Take for example the Sequence Dart: http://www.premiumaquatics.com/Merc...ct_Code=SQ-REEFLO18-SW&Category_Code=Sequence
hth,
rob
I stand corrected.<a href=showthread.php?s=&postid=10379101#post10379101 target=_blank>Originally posted</a> by BeanAnimal
nasek, I don't think you have a firm grasp of how centrifugal pumps operate. They are ALL veribale electric current.
As head increases, output decreases. As output decreases, so does power usage.
We can plot this power usage vs output on a graph. We would call it a pump curve.
Each motor-impeller-volute combination has a "sweet spot" or BEP (Best operationg point) where flow-per-watt is maximized. On either side of BEP flow-per-watt decreases.
That is all fine and dandy... but you are also missing another point.
Pump do WORK. They lift water. Water has weight and therefore takes energy to move. Moving water 100 vertical feet takes more energy than moving water 10 vertical feet. Either the pump does less work, or the water has less energy when it gets to the finish height. Becuase these are NOT positive displacement pump, we get a little bit of both.
The water at the 100' head has much less pressure at the nozzle exit than does the water at the 10' exit.
BUT DO NOT FORGET that 100W pump at 100' moves 10GPM and at 10' It moves 100GPM.
So we have
100W at 100' = 10 gallons = 10 Watts per gallon of water moved
100W at 10' = 100 Gallons or 1 Watt per gallon of water moved
That is ALL without the current changingI.E. an assumed linear relationship, not a curve.
For a real world numbers lesson, just look at a pump curve...
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Notice the CURVE showing the power consumption (variable is the term you used...)
GPH _ _HEAD _ WATTS _ GpW
0 _ _ _ 12 _ _ _110 _ _ _0
600 _ _11 _ _ _130 _ _ _4.6
1200 _ 10 _ _ _145 _ _ _8.3
1800 _ 08 _ _ _158 _ _ _11.4
2400 _ 06 _ _ _160 _ _ _15
3000 _ 03 _ _ _155 _ _ _19.4
3600 _ 00 _ _ _140 _ _ _25.7
I hope you can use this information to better understand the realationship to pump outout vs power consumed.
<a href=showthread.php?s=&postid=10379161#post10379161 target=_blank>Originally posted</a> by BeanAnimal
The day is wasted unless you learn something!
<a href=showthread.php?s=&postid=10379236#post10379236 target=_blank>Originally posted</a> by BeanAnimal
Capn...
It is not so much experience. It is a willingness to learn and understand. I learn every day simply by paying attention to the world around meI am humbled daily in one way or another.
<a href=showthread.php?s=&postid=10379220#post10379220 target=_blank>Originally posted</a> by BeanAnimal
"head" is a measure of the resistance to flow. This can be from gravity (vertical lift) or from resistance due to plumbing and other restrictions.
You can decrease the power consumption of the pump be restricting the output. You will however also restrict the outputThat likely means less flow per watt consumed.
The question then becomes simple. If I can get away with LOWER flow, then why don't I buy a smaller pump that will operate at better efficiency?
You can do this by comparing pump curves of pumps in the range of flows you are contemplating.
Study the pump curve above and notice how the relationship is not linear.