This just needs to be done, as it was brought up else where 
What about 13 3/4#, 14# & 15# pound packages of like chemistry making the same salinity solution? It is not going to happen.
Simple math and reading Craig's report. He weighed out 35 grams of each salt and added it to water to give a final vol of 1 L. He then measured the salinity. They ranged from 2-7 ppm lower than NSW. Why ? The weight of the water in the salt mixes. Each 35 grams had between 2- 7 grams of water in them.
Lets pretend there is salt with zero water in, thus 35 grams in 1 L would yield 35 ppt. And another salt of 35 grams yields 30 ppt, as 5 grams of that 35 grams is water.
30/35 = 15% and 15 % of 15 lbs = 2.25 lbs. 15 -2.25 =12.27 lbs. That means that a bag of salt with no water will yield a salinity of 30 ppt if it weighed 12.75 lbs and a bag with 5 grams of water/35 grams weight, would need a weight of 15 lbs to give the same salinity of 30 ppt.
So, that is a 12.75 lb bag vs 15 lbs bag both giving the same salinity, of like chemistry, in the same number of gallons of water and both giving 30 ppt salinity.
and that is like chemistry making the same salinity solution? No proof or documents required. It is simple weight vol. relationships. And one could expand on this with 2 grams, 3 grms, etc., of water / 35 grams of salt in a 1 L solution.
I had posted when the thread was locked, so it did not get posted.
Sorry if I should not have brought it up in this thread but this needed to be resolved.

What about 13 3/4#, 14# & 15# pound packages of like chemistry making the same salinity solution? It is not going to happen.
Simple math and reading Craig's report. He weighed out 35 grams of each salt and added it to water to give a final vol of 1 L. He then measured the salinity. They ranged from 2-7 ppm lower than NSW. Why ? The weight of the water in the salt mixes. Each 35 grams had between 2- 7 grams of water in them.
Lets pretend there is salt with zero water in, thus 35 grams in 1 L would yield 35 ppt. And another salt of 35 grams yields 30 ppt, as 5 grams of that 35 grams is water.
30/35 = 15% and 15 % of 15 lbs = 2.25 lbs. 15 -2.25 =12.27 lbs. That means that a bag of salt with no water will yield a salinity of 30 ppt if it weighed 12.75 lbs and a bag with 5 grams of water/35 grams weight, would need a weight of 15 lbs to give the same salinity of 30 ppt.
So, that is a 12.75 lb bag vs 15 lbs bag both giving the same salinity, of like chemistry, in the same number of gallons of water and both giving 30 ppt salinity.

and that is like chemistry making the same salinity solution? No proof or documents required. It is simple weight vol. relationships. And one could expand on this with 2 grams, 3 grms, etc., of water / 35 grams of salt in a 1 L solution.
I had posted when the thread was locked, so it did not get posted.
Sorry if I should not have brought it up in this thread but this needed to be resolved.