michael_in_nc
New member
I would recommend that the LED's not be driven in "parallel" like this connection. It may very well work but it's risky. You could easily burn out some of your expensive LED's. Here's why I'm concerned:
The LED is a diode. The diode's voltage is V ~ Vt*ln( I / Is ). This means the diode's forward voltage is logarithmically related to the bias current, so a small change in voltage results in a large change in current. So, if you hook a stack of 6 LED's in parallel with 5 more of them, you could easily get a diode stack that is slightly different in forward voltage (variations in Is, the diode's semiconductor properties or parasitic resistances). This can cause a runaway condition over time. If one branch pulls slightly more current, it will get hotter. This activates the other sensitivity. The forward voltage is temperature dependent. So, the hotter is gets, the lower it's forward voltage which means it pulls even more current (more power = more heat) and so on.
I'm an electrical engineer, so I deal with this stuff on a daily basis, having said that I don't normally deal with LED's or diodes operating at this power level, so there may well be secondary effects I'm not considering. Just wanted to give you a heads up that this could be risky. One way to check what I'm saying is to put an ammeter in series with each string and see if the current is really splitting the way it should. Relatively easy check.
The LED is a diode. The diode's voltage is V ~ Vt*ln( I / Is ). This means the diode's forward voltage is logarithmically related to the bias current, so a small change in voltage results in a large change in current. So, if you hook a stack of 6 LED's in parallel with 5 more of them, you could easily get a diode stack that is slightly different in forward voltage (variations in Is, the diode's semiconductor properties or parasitic resistances). This can cause a runaway condition over time. If one branch pulls slightly more current, it will get hotter. This activates the other sensitivity. The forward voltage is temperature dependent. So, the hotter is gets, the lower it's forward voltage which means it pulls even more current (more power = more heat) and so on.
I'm an electrical engineer, so I deal with this stuff on a daily basis, having said that I don't normally deal with LED's or diodes operating at this power level, so there may well be secondary effects I'm not considering. Just wanted to give you a heads up that this could be risky. One way to check what I'm saying is to put an ammeter in series with each string and see if the current is really splitting the way it should. Relatively easy check.