New EcoTech Marine Vectra Return Pump

I put a M1 online last night in closed loop mode on Reef Crest yellow setting. The pump is mounted external and I am surprised how hot it is running and it ramps up and down. It is more than warm to the touch. I will look at my graphs in a few days to see if anything changed temp wise on Apex, this pump replaced a Reef Octopus 5500 DC pump on a closed loop on my frag tank.
Looking forward to hearing what your apex data reveals on tanks temperature.
Hopefully all is good.
 
It's two people now as pciscott mentioned on post 453. When there is smoke there is fire.
[emoji83] [emoji84] [emoji91]

He has a real problem and we have been trying to trouble shoot a new product. He is an experience aquarist with a good rep. on RC.

RJ
 
It's two people now as pciscott mentioned on post 453. When there is smoke there is fire.
[emoji83] [emoji84] [emoji91]

This whole thing is exhausting, It is two people. All pumps will give off some heat. Yes some heat of course will go into system. But there is no "if there is smoke there is fire kinda thing". I don't see any issue on this and I am normally all about conspiracy theories.
 
I think we need more users to comment if the pump is hotter than norm. Too early to say either way, and in my book the jury is still out.
 
This whole thing sounds weird. There must be another factor playing a role into your increase. You have a lot of the same equipment as me and I do not have any noticeable increase in temperature. An 80w pump won't raise a 120g tank 5 degrees and if you are running it at 40w, it would play a small role in the temp of the tank. We need to move past one person "alleged" issue. It just sounds like you don't like it and are looking for a way to return it claiming an issue.
I said exchange not return. My hope was something was wrong with my pump, not the line. I was interested in exchanging mine for another.

If I didn't like the pump I would have said it and not wasted my time.
 
If you put a pump in the sump that is using 50 watts more then your old pump. it is pretty much the same as adding a 50 watt heater that is on all the time to your system. The amount of heat introduced when run externally will be substantially less as most of the heat is dissipating to the air around the pump. One big advantage of external pumps is much less heat transfer depending on the pump. Running the pump internally will keep it cooler, so it should last longer.
 
You are right 60-70watts vs 145 watt for the MAG18. It just the cooler temp. make it impossible to know why something is happening. If you ask what I believe, I think the M1 runs far more cooler than the MAG18. Wattage figures do not lie. But, so far, I have been unable to measure this.

RJ

I agree.
 
If you put a pump in the sump that is using 50 watts more then your old pump. it is pretty much the same as adding a 50 watt heater .... The amount of heat introduced when run externally will be substantially less as most of the heat is dissipating to the air around the pump. One big advantage of external pumps is much less heat transfer depending on the pump.

This

You are correct for external pumps but for internal pump it is effectively a heater. The RD3 does loose some heat through the controller but if used internally all watts going into the pump motor would exit the pump as heat. The Ecotech also looses heat in the same manner but if internal it's gonna put out as much heat as is going to the pump motor as well just like any other pump.

And this.

Wouldn't how that pump dissipates heat be a factor?
No. If it is submersed, the power used by the pump is dissipated into the water as heat.

Or wouldn't how many watts used at the pump vs controller be a factor? If one pump which uses more power at the pump than another which uses less at the pump and more at the controller feels cooler than the other then wouldn't that be an indicator?
Yes, the power consumed by the controller will count towards the total power used, but unless there is a significant defect in the controller, the power consumption shouldn't vary much from unit to unit. Even it it does, that will not affect how much the pump heats the water. What you are hypothesizing is that one pump/controller combo has a pump that is using significantly less energy than average and at the same time a controller that is using significantly more; essentially two defects that occur at the same time to offset each other. Possible but very unlikely.

I don't think there is any way to know how much power is being used at the pump vs. controller except perhaps with the Vectra where ESL displays only the pump wattage used.
In general no. There are ways of indirectly measuring current and voltage, but most of us won't be able to do that.


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As gcarroll said, internal vs external is a totally different game. With internal all of the power consumed is transferred to the water. With external pumps, it is either transferred to the water or to the air. The relative proportion of these depends very much on the design of the pump. Your RD3 pump is not somehow keeping all the power consumption in the controller, rather is just more efficient at dissipating the heat to the air so it doesn't transfer it to the water.
 
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No. If it is submersed, the power used by the pump is dissipated into the water as heat.

Your RD3 pump is not somehow keeping all the power consumption in the controller, rather is just more efficient at dissipating the heat to the air so it doesn't transfer it to the water.

How then could one pump be more efficient at dissipating the heat outside of water but not inside?

The RD3 is 80w at the wall and the M1 is 90. With the RD3 having a controller it could be 70w at the pump and the M1 80 at the pump.

I'm very very tempted to use a Fluval SP4 in the same application to compare temps. It's an 88w pump but AC. No controller. Theoretically all 88w of heat will go into the water. The tank water should then increase from what it is now. Something I found interesting in that pump's advertising is "Low heat transfer to energy consumption. Fluval pumps run at a relatively cool temperature to avoid affecting the water temperature of the tank, whether running internally or externally." Not sure exactly what that means if 88w in is 88w out.
 
I would like to get back to all users experiences with the system that makes up the Vectra and controllers. Heat is just one aspect and doubt it of major importance.

One last thing about this heat discussion. I am not an engineer or scientist and I am sure there are others out there better suited to explain all this but I will give one LAST attempt as I understand it.

First, it is very good general rule to say watts mean added heat in the aquarium. A 100 watt...pick your equipment... will put more heat into your system than a 50 watt version of the same type of equipment. But just because any piece of equipment consumes a certain amount of power does NOT mean all 80 watts are converted to heat. That would make the equipment 100% efficient and nothing is 100% efficient. In fact our heaters are far more efficient in producing heat from electrical power than pumps. I know I am stating the obvious but I think this needed to be said.

Pumps use those watts to do work and, as a by-product, heat. DC pumps are more efficient than AC pumps that is why they can move the same amount of water using less power. than an AC version. So DC pumps also produce less heat. So an 80 watt pump DOES NOT produce 80 watts worth of heat. A good bit of the power goes moving the impeller thus moving water. Some pumps produce less heat for a certain amount of work- moving water. There are many variables as why one pump would be more efficient than others and I will let that go as you can already figure out most or all of them.

If I am wrong on the above, I invite someone with more experience in this field to explain the error of my ways. If not, a lot of what has been previous said, right or wrong or just confused has taken up much space. So some 80 watt pumps are more efficient than others. It is too early to understand where exactly where the Vectra stands.

I sure would like to hear from other Vectra owners about their install, use and satisfaction or disappointment in their pumps.

RJ
 
Im really curious to see if there's any heat transfer thru the prop housing on an external application. Temp issues could be a deal breaker for me.

I would expect to see some (particulately with a convection cooled pump), though I'd expect it to be just a small fraction compared to an internal installation.
 
One last thing about this heat discussion. I am not an engineer or scientist and I am sure there are others out there better suited to explain all this but I will give one LAST attempt as I understand it.

First, it is very good general rule to say watts mean added heat in the aquarium. A 100 watt...pick your equipment... will put more heat into your system than a 50 watt version of the same type of equipment. But just because any piece of equipment consumes a certain amount of power does NOT mean all 80 watts are converted to heat. That would make the equipment 100% efficient and nothing is 100% efficient. In fact our heaters are far more efficient in producing heat from electrical power than pumps. I know I am stating the obvious but I think this needed to be said.

I am an engineer and while I don't want to pick your statement apart it is incorrect. The water moved by a pump requires energy to move it, this part of your statement is correct. What you are missing is that the water that is moved holds energy and as the water slows to a stop due to friction will release that energy as heat. Thus 100% of the energy supplied to an internal pump is transferred to the water as heat. A 100w submersible pump and a 100w heater supply exactly the same amount of heat to a water column. A watt is a unit of heat.

I just logged in after a few weeks of drowning in work + some personal issues and am honestly surprised at where this thread is. I'm going to take a minute and see how you folks got here...
 
I am an engineer and while I don't want to pick your statement apart it is incorrect. The water moved by a pump requires energy to move it, this part of your statement is correct. What you are missing is that the water that is moved holds energy and as the water slows to a stop due to friction will release that energy as heat. Thus 100% of the energy supplied to an internal pump is transferred to the water as heat. A 100w submersible pump and a 100w heater supply exactly the same amount of heat to a water column. A watt is a unit of heat.

I just logged in after a few weeks of drowning in work + some personal issues and am honestly surprised at where this thread is. I'm going to take a minute and see how you folks got here...

Never taken a fluid dynamics course in my life so I have some trouble with this as I wonder where all the heat genterated from 5 submerged pumps and 2 prop pumps goes? Think I have a total or around 300 watts from these sources and I STILL HAVE TO USE a 300 watt heater to maintain a 2-3 degree differerent with my house? It seems to me you are saying a pump it a machine that is 100% efficient as a heater? Does not make sense to me.....

Thanks for the input and I look forward to hearing more although we might want to transfer to another thread.

RJ
 
What you are missing is that the water that is moved holds energy and as the water slows to a stop due to friction will release that energy as heat. Thus 100% of the energy supplied to an internal pump is transferred to the water as heat.

1st law of thermodynamics

I'm tagging along hoping for more reviews of the pump, less about the anecdotes of excessive heat transfer!
 
Evaporation. It takes 540 calories to evaporate 1 gram of water. A gallon of water evaporation is slightly over 2 million calories of heat energy removed from your tank. Our tanks typically have a ton of surface area and evaporate a lot of water per day so 40watts is typically insignificant on a 120gal tank.

It would take 40w of heat ~36 hours to increase an insulated 120gal barrel of water by 5 degrees but we don't have insulated barrels of water.

This is a great article from Advanced Aquarist that gives you all the formulas to figure this stuff out as well as explains many factors in great detail.
http://www.advancedaquarist.com/2009/7/aafeature1

Jonseye, are you using heaters on this system? How many gallons of water are you evaporating per week or day? Do you run a fan?

BTW if anyone wants to know how hot 40 watts really is... grab a 40w light bulb and turn it on.
 
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The AC to DC conversion is happening in the power supply. We can assume the power supply is rated at greater than 90% efficiency. Isn't the Vectra using a Meanwell supply? The particular model shown in the photo I saw was 93.5% efficiency. There will be a slight bit of losses in the controller but unless the controller runs hot or has a large heat sink I doubt it adds much significance in that number.

Mass of the submersed part or its physical size makes no difference in the overall thermal transfer. It may take longer to reach equilibrium but if it's holding heat in and not letting it dissipate it would melt down in short order. It must reach an equilibrium or temps will continue to rise until failure.

A larger heat sink will run cooler to the touch but if you cool 80 watts through a smaller heat sink it will just run hotter to the touch. It will still however dissipate 80 watts once it reaches equilibrium, if it doesn't like above it will simply self destruct.



86w x .935 = 80.41w & 78w x .935 = 72.93w. It appears that the ecosmart live program is showing actual motor power and not wall power.


Early pre-production pumps did have Meanwell power but the M1 has a no name black brick made in China. Don't know about the L1 as they have just shipped from Eco Tech. The controller does indeed have a hefty heat sink attached.

Yes, the EcoSmart Live program is showing only pump watts not controller power supply. Tim Marks mention this in his interview with Jake Adams. The 80 watts number is confined only to pump.


RJ
 
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