TheFishMan65
New member
He means parallel not series. Add a fuse a little above your maximum desired current for each string (and order spares).
I read a post that the harmonics 'could' lead to the wires overheating and catching fire. How many Meanwells per 15A circuit would be acceptable?
The HLGs would be much preferable-if only you could buy the dang things. Seems no vendors have the guts to order a case. Since vendors don't make fixtures they look at the ridiculous number of models offered in the HLG series and decide to stock nothing. Instead they should note we really work with the 42 to 48V series and just stock those. But I digress.
Definitely go parallel. Especially if you use the infernal ELNs..
Here's a thread that shows the parallel method. I think I listed the resistors fuses and terminal blocks in there too.
http://www.reefcentral.com/forums/showthread.php?t=1974104&
Ok I am running the leds through my Apex lite. So I am not dimming (doing that though simple pots) the leds through the Apex, just on/off. The Apex gives a amps readout on your system. When I turn the system on full blast it is not pulling the amps I expected. I have 2 strings running at 1000 mA and 3 strings running at 700 mA. In theory this means this lighting should be pulling 4.1 A, plus a little for the fan ats full power correct? Instead at full blast the Apex is telling me I am drawing about 1.5 A total for my lights. Any explaination (not that i am complaining less stress on my home circut)?
I made mistake by writing it into forum, I have the formula in Excel table. I did correct the formula in my next post:
PAR/W = lambda / (c . h . NA) in mol of photons.m-2.s-1
h = 6.6626E-34 (Planck's constatnt)
c = 299792458 (Speed of Light)
NA = 6.02214E23 (Avogadro's number)
lamdba = 450nm = 4.5E-7 m (wavelength of Royal Blue)
Look at http://en.wikipedia.org/wiki/Photon
you can see there that energy of Photon is E = c. h / labmda in J (W.s-1)
Then look at Example problem #2 and #3: where they calculate inverse KJ/mol as E multiplied by Avogadro number. 241 KJ/mol inverted is 4.14E-6 mol/J (same result as you get from 496.36nm / (299792458 . 6.6626E-34 . 6.02212E23 ) = 4.13E-6 mol / J = 4.13 umol/J
http://www.chemteam.info/Electrons/LightEquations2.html
If we invert the equation we get umol/J and J per one second is Watt. So in the final we get umol/W formula:
umol/W = 1/ (E . Na)= lambda / (c . h . NA)i
The result you get is how many PAR you get from 1W of Radiant flux of Royal Blue per square meter. Cree XP-E Royal Blue gives you 500mW at 350ma, at 700ma around 900mW. If you get 3.76 umol for 450nm light then from 0.9W RB radiant flux of 2.4W (700mA*3.4V) of RB led you should get 3.4 umol.
If you put 41 Leds (~100W consumption) in one square meter you get average 41x3.4 = 140 umol per square meter. Focused in smaller area e.g. into 50x25 tank (0.75 sq. m) you get 140 / 0.75 = 187 umol/s into water surface of your tank.
To me it perfectly correlates with other calculations such as umol/lux, etc.
Marcer,
One thing is still bothering me about your formula. It does not seem to correctly account for optical spread or beam overlap. It seems to assume that there is even irradiance over the area from each LED which is not the case. There are no terms for angular light spread or distance. I do not understand how it could be accounting for the 1/r squared loss or overlap buildup. If I put a number of leds above a single square meter and space them on some even square grid. Depending on the optics I will have areas of high overlap where many areas of FWHM light cones overlap and other areas where this does not happen to the same degree. Your present formula seems to only look at the number as an overall average rather than a spot by spot addup.
Comments?
Mark
^^^^
Thomas Research makes high voltage drives as opposed to high current drivers (Meanwells ). Nanotuners is the only place that sometimes carries them. The issue there is high voltage is much more dangerous for you personally. 48 volts may hurt, 150 volts can kill.
From what I have read parallel can be done safely, but you must include a fastburn 1 A fuse one each individual string. Kcress has a nice writeup on it here http://www.reefcentral.com/forums/showthread.php?t=1751598. You can also use Meanwell's hln series, which are low voltage, high current drivers which work great of parallel applications. That series can run upto 4 strands of 14 depending on the specific driver and LED picked.
Hi,
I ordered the 48 diy kit from rapid led, my question is can you run the mean well on two power cords instead of four, and if yes how?
Thanks.
Yes, you can run multiple meanwells on the same plug, easiest way would be to use wire nuts I guess, or you could solder the wires, or use terminal blocks with jumpers, etc. Not sure what you are asking by how to do it?
Input Current: 0.90 A @ 100 VAC, 042 A @ 220 VAC